Cerebral distractions of every kind, mostly but not exclusively Countdown-related.
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James Hall
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by James Hall » Wed Jun 17, 2009 10:21 pm
Neil Zussman wrote: Also, is my way of making 3 from two 4's by using infinitely many square roots (posted earlier) legal?
Normally you're only allowed a finite number of functions.
Kai, the gamma function, as far as integers are concerned, is defined thus:
Γ(n) = (n-1)!
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Neil Zussman
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by Neil Zussman » Fri Jun 19, 2009 5:33 pm
Presumably Kai means we can use double factorial. Thus 4!!=8 and ((4!!)!!)/4=96.
This means 3=4!/4!!, i.e. 3 can be made using just two 4's. Thus 51, 45, 93 and 99 can now be made (see my previous post). I'm sure lots more numbers can be made as well, although interest in the puzzle seems to have waned.
Robert Baxter
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by Robert Baxter » Mon Aug 30, 2010 4:53 pm
33:
(4*4*sqrt 4)+sqrt 4
4!+(4!/4)+4
sqrt(4^4)*sqrt 4+sqrt 4
Edit: Told you I was an
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Kai Laddiman
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by Kai Laddiman » Mon Aug 30, 2010 4:57 pm
Robert Baxter wrote: 33:
(4*4*sqrt 4)+sqrt 4
4!+(4!/4)+4
sqrt(4^4)*sqrt 4+sqrt 4
Edit: Told you I was an
There's only 3 there, not 33. Typo perhaps?
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Robert Baxter
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by Robert Baxter » Mon Aug 30, 2010 5:11 pm
Kai Laddiman wrote: Robert Baxter wrote: 33:
(4*4*sqrt 4)+sqrt 4
* 4!+(4!/4)+4
sqrt(4^4)*sqrt 4+sqrt 4
Edit: Told you I was an
There's only 3 there, not 33. Typo perhaps?
Does this work?
Contestant: Continent please, Rachel.
Rachel: Y.
Contestant: Because I want one!
For more info, see
http://wiki.apterous.org/User:The_Doctor , and don't have a go at me a the F1 drivers series.
The 86th postingest forummer.
And I'm a
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